50=-0.2x^2+2x+45

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Solution for 50=-0.2x^2+2x+45 equation: 



50=-0.2x^2+2x+45

We move all terms to the left:

50-(-0.2x^2+2x+45)=0

We get rid of parentheses

0.2x^2-2x-45+50=0

We add all the numbers together, and all the variables

0.2x^2-2x+5=0

a = 0.2; b = -2; c = +5;
Δ = b2-4ac
Δ = -22-4·0.2·5
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{2}{0.4}=5$

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